Activating Samarium Diiodide Reagent (IMAGE) California Institute of Technology Caption This image shows different stages of a chemical reaction with the samarium diiodide reagent. The flask on the left contains a yellow, inactive form of the compound—over time, the compound becomes active and turns purple, as seen on the right. This color change occurs because the oxidation state of the Samarium reagent changes from 3+ to 2+ , or from Sm(III) to Sm(II), which means it gains an electron. Credit Caltech/Chungkeun Shin Usage Restrictions No restrictions. License CC0 Disclaimer: AAAS and EurekAlert! are not responsible for the accuracy of news releases posted to EurekAlert! by contributing institutions or for the use of any information through the EurekAlert system.