Activating Samarium Diiodide Reagent (IMAGE)
Caption
This image shows different stages of a chemical reaction with the samarium diiodide reagent. The flask on the left contains a yellow, inactive form of the compound—over time, the compound becomes active and turns purple, as seen on the right. This color change occurs because the oxidation state of the Samarium reagent changes from 3+ to 2+ , or from Sm(III) to Sm(II), which means it gains an electron.
Credit
Caltech/Chungkeun Shin
Usage Restrictions
No restrictions.
License
CC0